Question

9. An oil drop has -6.39 x 10-19 C charge. Fi
number of electrons in this oil drop.
(a) 2
(b) 4
(c) 6
(d) 8​

Answer 1

Answer

b)4

Explanation

Q=ne

where,

Q is charge,

n is number is electrons and

e is charge of one electron.

$- 6.9 \times {10}^{ - 19} = n \times - 1.6 \times {10}^{ - 19}$

charge in one electron is 1.6×10^-19 coulomb.

$n = \frac{ - 6.39 \times {10}^{ - 19} }{ - 1.6 \times {10}^{ - 19} }$

$n = \frac{ - 6.39}{ - 1.6}$

$n = 3.99 = 4$

Please mark my answer as brainliest!