Question

9. At a post office there are three parcels of different masses. The mass of the first
parcet is yg The mass of the second parcel is 500 g greater than that of the first
parcel. The third porcel is 210 g lighter than the first parcel.
(a) Find the total mass in grams of the three parcels in terms of y.
(b) The total mass of the three parcels is 2 kg. Find the mass of each parcelin
grams​

Answer 1

Step-by-step explanation:

(a)The mass of the first

parcet is yg

The mass of the second parcel is 500 g greater than that of the first parcel=500+y

The third parcel is 210 g lighter than the first parcel=y-210

total=y+500+y+y-210=3y+290

(b) The total mass of the three parcels is 2 kg.

then y+500+y+y-210=2kg=2000g

3y+290=2000

3y=2000-290

3y=1710

y=1710/3

y=570...1st parcel mass

2nd parcel mass=500+y=500+570=1070

3rd parcel mass=y-210=570-210=360

Answer 2

Answer:

yg is the answer of this question