Question

9. At a post office there are three parcels of different masses. The mass of the first
parcet is yg The mass of the second parcel is 500 g greater than that of the first
parcel. The third porcel is 210 g lighter than the first parcel.
(a) Find the total mass in grams of the three parcels in terms of y.
(b) The total mass of the three parcels is 2 kg. Find the mass of each parcelin
grams​

Answer 1

Answer:

1st parcel =y g

2nd parcel = y + 500 g

3rd parcel = y - 210 g

total wt = y + y +500 +y -210 = 3y +290 g

3y + 290 = 2000 g

3y = 2000-290 = 1710

y = 1710÷3 = 570 = mass of 1st

570+500 = 1070 = mass of 2nd

570 - 210 = 360 = mass of 3rd