Question

9.
At t=0 a 1.0 kg ball is thrown from the top of a ball tower with velocity y = (8î+9j) m/s. The
change in the potential energy of the ball-earth system between t=0 to t= 5s: (g= 10 m/s)
a)-800J
b) 1536J
c) 2100J
d) none of these
​

Answer 1

Answer:

none of these is the answer.

Answer 2

Answer:

The

change in the potential energy of the ball-earth system between t=0 to t= 5s (g= 10 m/s) is -1314J.

Explanation:

It is given in the question that,

mass of the substance is, m = 1 kg.

Now, According to the formula,

$S_y=U_yt+(\frac{1}{2} \times a_yt^2)\\S_y=9\times 5+\frac{1}{2}(-9.8)\times 36\\ S_y=-131.4m$

Where, $S_y$ is the height in the vertical distance.

$U_y$ is the speed of falling the ball at vertical length .

$a_y$ is the acceleration force and t is time of falling.

Now,

Potential energy, $\Delta U=mgh$

where, m is the mass of the substance.

g is the gravitational force which is given in the question as 10 m/s and h is the height of the substance from the ground.

Now, Substitute the given data in the respective formula,

$\Delta U=mgh\\\Delta U=1kg\times 10ms^{-1}\times (-131.4m)\\\Delta U=-1314J$

Hence the correct answer is option (d) none of them.

To know more  about change in potential energy, click on the link given below,

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