Question

9. At the same temperature carbon monoxide
molecules have the same most probable
velocity as the molecules of​

Answer 1

As we know that the most probable speed (V) of a molecule is given by-

V=  

M

2RT

​  

 

​  

 

For the same gas-

V∝  

T

​  

 

⇒  

V  

2

​  

 

V  

1

​  

 

​  

=  

T  

2

​  

 

T  

1

​  

 

​  

 

​  

.....(1)

Let the most probable speed of CO  

2

​  

 molecule at 127℃ be Vm/s.

Let the most probable speed of CO  

2

​  

 molecule be 2Vm/s at temperature TK.

Now according to the question, we have to find T.

Here,

V  

1

​  

=Vm/s

V  

2

​  

=2V;m/s

T  

1

​  

=127℃=(127+273)K=400K

T  

2

​  

=TK

Now from eq  

n

(1), we have

2V

V

​  

=  

T

400

​  

 

​  

 

⇒  

T

400

​  

 

​  

=  

2

1

​  

 

Squaring both sides, we get

T

400

​  

=  

4

1

​  

 

⇒T=1600K

Hence the required answer is 1600K.

Answer 2

Answer:

nitrogen

Explanation:

molecular weight same then probable velocity equal

co=28

N2=28

• ans is nitrogen
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