Question

9. At what rate will 14000 lent for 4 years fetch an interest of 10080?

10. What sum of money lent at 13% p.a. for 3 years fetches an interest of 33900?​

Answer 1

Step-by-step explanation:

Question 1:-

Given:-

• Principal = Rs.14000

• Simple Interest = Rs.10080

• Time = 4 years

To Find:-

• The rate of Interest

Solution:-

As we know that:-

The formula for finding Rate is:-

$\boxed{ \sf \leadsto R = \dfrac{I \times 100}{P \times T} }$

Where:-

• R = rate of Interest = ?

• I = Interest = Rs.10080

• P = Principal = Rs.14000

• T = Time = 4 years

Substituting the values:-

$\sf \implies R = \dfrac{10080 \times 100}{14000 \times 4}$

$\sf \implies R = \dfrac{1008000}{56000}$

$\sf \implies R = 18\%$

$\underline{\boxed{\sf \therefore Rate \: of \: Interest = 18\%}}$

Question 2:-

Given:-

• Rate of Interest (R) = 13%

• Time (T) = 3 years

• Simple Interest (SI) = 33900

To Find:-

• The sum of money lent (Principal)

Solution:-

As we know that:-

The formula for finding Principal is:-

$\boxed{ \sf \leadsto P = \dfrac{I \times 100}{R \times T} }$

Substituting the values:-

$\sf \implies P = \dfrac{33900 \times 100}{13 \times 3}$

$\sf \implies P = \dfrac{3390000}{39}$

$\sf \implies P \approx 86923$

$\underline{\boxed{\sf \therefore Sum \: of \: money \: lent \approx Rs.86923}}$

Answer 2

$\huge{\boxed{\rm{\red{Question \: 9}}}}$

At what rate will 14000 lent for 4 years fetch an interest of 10080?

$\huge{\boxed{\rm{\red{Answer \: 9}}}}$

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• Principal ( P ) = Rupees 14000.
• Time period ( T ) = 4 years.
• Simple Interest ( S.I ) = Rupees 10080

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

• Interest's rate ( R )

${\bigstar}\large{\boxed{\sf{\pink{Solution}}}}$

$\large\purple{\texttt{The formula to find Interest's rate ➝}}$

$\frac{si \: \times 100}{p \: \times \: t}$

$\large\orange{\texttt{Here we write}}$

⚪Time period as T

⚪Simple Interest as SI

⚪Principal as P

⚪Interest's rate as R

$\large\pink{\texttt{By substituting the values we get}}$

$\frac{10080 \times 100}{14000 \times 4}$

$\frac{1008000}{56000}$

By cancelling the zeros and divide the remaining terms we get 18.

$\large\red{\texttt{18 percent is rate}}$

$\huge{\boxed{\rm{\red{Question \: 10}}}}$

What sum of money lent at 13% p.a. for 3 years fetches an interest of 33900 ?

$\huge{\boxed{\rm{\red{Answer \: 10}}}}$

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• Interest's rate = 13% ( R )
• Time period = 3 years ( T )
• Simple Internet = 33900 rupees ( SI )

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

• The Principal ( P )

${\bigstar}\large{\boxed{\sf{\pink{Solution}}}}$

$\large\purple{\texttt{The formula to find Principal ➝}}$

$\frac{i \: \times \: 100}{r \: \times \: t}$

$\large\pink{\texttt{By substituting the values we get}}$

$\frac{33900 \: \times \: 100}{13 \: \times \: 3}$

$\frac{3390000}{39}$

By dividing 3390000 by 39 we get 86923 Rupees.

$\large\red{\texttt{Rs 86923 is Principal}}$

@Itzbeautyqueen23

Hope it's helpful.

Thank you :)