Question

9 b square + 12 BC + AC square​

Answer 1

$\red{ \huge{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: QUESTION \: \: \red{ \mid}}}}}}}}$

$\underline{\underline{ \red{ \textbf{ \textsf{ \: SIMPLIFY \: : }}}}} \: \: \: \: \: \bold{9b {}^{2} + 12 bc + 4c {}^{2} }$


$\red{ \huge{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \:SOLUTION \: \: \red{ \mid}}}}}}}}$


$\bold{9b {}^{2} + 12bc + 4c {}^{2} } \\ \\ \bold{ = (3b) {}^{2} + 2 \times 3b \times 2c + (2c) {}^{2} } \\ \\ \bold{ = (3b + 2c) {}^{2} } \\ \\ \bold{ = (3b + 2c)(3b + 2c)}$

Answer 2

Answer:

=(3b+2c) square

Step-by-step explanation:

9b2 +12bc + 4b2

= 9b2 + (6+6)bc +4c2

= 9b2 + 6bc + 6bc + 4c2

=3b(3b+2c) + 2c(3b+2c)

=(3b+2c)^2

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