Question

9. Calcualte the mole fraction of ethanol (C2H5OH) in the solution containing 20g of ethanol and 100 g of
water.
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Answer 1

Answer:

0.00768131475

Explanation:

THE NO OF MOLES OF ETHANOL=20/46  = .43

THE NO OF MOLES OF WATER IS = 100/18 = 55.5

MOLE FRACTION OF ETHANOL = NO OF MOLES OF C₂H₅OH / TOTAL MOLE

= $\frac{.43}{55.98}$= .007681

Answer 2

Answer:

Explanation:

mole fraction of ethanol =  no.of moles of ethanol / total no.of moles

here total no.of moles = no.of moles of ethanol +no.of moles of water

no.of moles of ethanol = given mass /GAM

                                      = 20 / 46

                                       =0.43

no.of moles of water = 100/18

                                   =5.55

total number of moles = 0.43 +5.55

                                     = 5.98

mole fraction of ethanol = 0.43/5.98

                                        =0.07