Question

9. Calculate the mass of oxygen gas chose
volume
2 atmose-
pressure
is
beric​

Answer 1

Answer:

Given

Temperature, T=273+27=300K

760 mm mercury pressure, P=10

5

Pa

Volume, V=11.2L=11.2×10

−3

m

3

Gas constant for oxygen, R=

M

R

=

32

8314

=259Jkg

−1

K

−1

From ideal gas equation,

PV=n

R

0

T

PV=

M

m

R

0

T=mRT

m=

RT

PV

=

259×300

10

5

×11.2×10

−3

=0.0144kg=14.4gram

Hence, mass of gas is 14.4gram

Answer 2

Answer:

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