Question

9) Calculate the work done in moving a charge of 5 C from a point at a potential of 210 volts to
another point at 240 V ​

Answer 1

To Find :

• we need to find the work done to move a charge of 5C.

Given :

• Potential difference (v) = 210 to 240 v
• charge = 5 coulamb
• work done = ?

Solution :

We know that,

• potential difference = work/charge
• Work done = potential difference × charge

w = 5 × (240 - 210)

w = 5 × 30

w = 150 joules.

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Potential Difference :

work done to move a charge Q from one point to another is called potential difference.

• SI unit = volt (V)

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Answer 2

Answer:

W = 150 J

Explanation:

Given,

Q = 5 C

V1 = 210 V

V2 = 240 V

To find : W = ?

V2 - V1 = 240 - 210

V2 - V1 = 30 V

V = W / Q

W = V Q

   = ( V2 - V1 ) x Q

   = 30 x 5

W = 150 J

Therefore, the work done in moving a charge of 5 C from a point at a potential of 210 volts to  another point at 240 V is 150 J.