Question

9 Chairs and 5 tables cost rupees 90 while 5 chairs and 4 tables cost rupees 61. Find the price of 6 chairs and 3 tables.​

Answer 1

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Step-by-step explanation:

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Answer 2

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Cost\:of\:6\:chairs\:and\:5\:tables=57\:rupees}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about 9 Chairs and 5 tables cost rupees 90 while 5 chairs and 4 tables cost rupees 61.

• We have to Find the price of 6 chairs and 3 tables.

$\bold{Assuming : } \\ \implies Let \: Cost \: of \: one \: chair = c \\ \\ \implies \: Cost \: of \: one \: table= t\\ \\ \underline \bold{Given : } \\ \implies 9c + 5t = 90 \\ \\ \implies 5c + 4t = 61 \\ \\ \underline \bold{To \: Find : } \\ \implies Cost \: of \: 6 \: chair = ? \\ \\ \implies Cost \: of \: 3 \: tables = ?$

• According to given question :

$\implies 9c + 5t = 90 - - - - - (1) \\ \\ \implies 5c + 4t = 61 - - - - - (2) \\ \\ \bold{Using \: substitution \: method : } \\ \\ \bold{On \: solving \: (1) \: we \: get \to} \\ \implies 9c = 90 - 5t \\ \\ \implies c = \frac{90 - 5t}{9} - - - - - (3) \\ \\ \bold{Putting \: value \: of \: c \: in \: (2)} \\ \implies 5c + 4t = 61 \\ \\ \implies 5 \times \frac{(90 - 5t)}{9} + 4t = 61 \\ \\ \implies \frac{450 - 25t + 36t}{9} = 61 \\ \\ \implies 450 + 11t = 549$$\implies 11t = 549 - 450 \\ \\ \implies t = \frac{99}{11} \\ \\ \bold{\implies t =9 \: rupees} \\ \\ \bold{Putting \: value \: of \: t \: in \: (3)} \\ \implies c = \frac{90 - 5 \times 9}{9} \\ \\ \implies c = \frac{90 - 45}{9} \\ \\ \implies c = \frac{45}{9} \\ \\ \bold{\implies c = 5} \\ \\ \bold{\therefore Cost \: of \: 6 \: chairs \: and \: 3 \: tables= 57 \: rupees}$