9 cm long object is placed at 90 cm from a spherical mirror perpendicular to its principal Axis a real image is formed at 30 cm from the mirror then the radius of curvature of the mirror is ___cm
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2
Answer:
here's the answer
Explanation:
22.5 cm
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Answer:
Height of object ho = 9 cm
Focal lenght of convex lens = ? cm
Object distance u = -90 cm
Image distance v = 30 cm
Image height hi = ?
Lens formula: 1/v - 1/u = 1/f
1/f = 1/v - 1/u
= 1/30 + 1/(-90)
= -1/45
⇒ v = - 45 cm
The image distance is 45 cm on the same side of the lens as the object.
Magnification m = v/u = (-45)/(-90) = 1/2 = hi/ho = hi/9
⇒ hi = 9/2 cm
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