Question

9 Convert (a) 108 km/hr into m/s (b) 90 km/hr to m/s (c) 18 km/hr to m/s (d) 80km/hr to m/s (e) 54km/hr to m/s​

Answer 1

Explanation:

As per the provided question, we have to convert km/h to m/s, basically. We need to know one thing given below, in order to tackle this question,

$\longmapsto\boxed{\bf{ 1 \; kmh^{-1} = \dfrac{5}{18}\;ms^{-1}}}$

(a) 108 km/hr into m/s :

$\longmapsto\rm { 1 \; kmh^{-1} = \dfrac{5}{18}\;ms^{-1}}$

$\longmapsto\rm { 108 \; kmh^{-1} =\Bigg ( 108 \times \dfrac{5}{18} \Bigg ) \;ms^{-1}}$

$\longmapsto\rm { 108 \; kmh^{-1} = ( 6 \times 5 ) \;ms^{-1}}$

$\longmapsto\bf { 108 \; kmh^{-1} =30 \;ms^{-1}}$

(b) 90 km/hr to m/s :

$\longmapsto\rm { 1 \; kmh^{-1} = \dfrac{5}{18}\;ms^{-1}}$

$\longmapsto\rm { 90 \; kmh^{-1} =\Bigg ( 90 \times \dfrac{5}{18} \Bigg ) \;ms^{-1}}$

$\longmapsto\rm { 90 \; kmh^{-1} = ( 5 \times 5 ) \;ms^{-1}}$

$\longmapsto\bf { 90 \; kmh^{-1} =25 \;ms^{-1}}$

(c) 18 km/hr to m/s :

$\longmapsto\rm { 1 \; kmh^{-1} = \dfrac{5}{18}\;ms^{-1}}$

$\longmapsto\rm { 18 \; kmh^{-1} =\Bigg ( 18 \times \dfrac{5}{18} \Bigg ) \;ms^{-1}}$

$\longmapsto\rm { 18 \; kmh^{-1} = ( 1 \times 5 ) \;ms^{-1}}$

$\longmapsto\bf { 18 \; kmh^{-1} =5 \;ms^{-1}}$

(d) 80km/hr to m/s :

$\longmapsto\rm { 1 \; kmh^{-1} = \dfrac{5}{18}\;ms^{-1}}$

$\longmapsto\rm { 80 \; kmh^{-1} =\Bigg ( 80 \times \dfrac{5}{18} \Bigg ) \;ms^{-1}}$

$\longmapsto\rm { 80 \; kmh^{-1} = ( 4.4 \times 5 ) \;ms^{-1}}$

$\longmapsto\bf { 80 \; kmh^{-1} =22.22 \;ms^{-1}}$

(e) 54km/hr to m/s :

$\longmapsto\rm { 1 \; kmh^{-1} = \dfrac{5}{18}\;ms^{-1}}$

$\longmapsto\rm { 54 \; kmh^{-1} =\Bigg ( 54 \times \dfrac{5}{18} \Bigg ) \;ms^{-1}}$

$\longmapsto\rm { 54 \; kmh^{-1} = ( 3 \times 5 ) \;ms^{-1}}$

$\longmapsto\bf { 54 \; kmh^{-1} = 15 \;ms^{-1}}$

Hence, we got the required answers!

Answer 2

Answer:

• To convert km/hr into m/s, multiply by $\frac{5}{18}$

a) 108km/hr

= (108 × $\frac{5}{18}$) m/s

= 6×5 m/s

= 30m/s

b) 90km/hr

= (90 × $\frac{5}{18}$) m/s

= 5×5 m/s

= 25m/s

c) 18km/hr

= (18 × $\frac{5}{18}$) m/s

= 1×5 m/s

= 5m/s

d) 80km/hr

= (80 × $\frac{5}{18}$) m/s

= 4.4×5 m/s

= 22m/s

e) 54km/hr

= (54 × $\frac{5}{18}$) m/s

= 3 × 5 m/s

= 15m/s