Question

9.
Derive expressions for Maximum height time of flight and range for an oblique
projectile?​

Answer 1

Answer:

The range (R) of the projectile is the horizontal distance it travels during the motion. Using this equation vertically, we have that a = -g (the acceleration due to gravity) and the initial velocity in the vertical direction is usina (by resolving). Hence: y = utsina - ½ gt2 (1)