Question

9. Efficiency of a Carnot engine is 50% when temperature of outlet is 500 K. In order to incre
efficiency up to 60% keeping temperature of intake the same what is temperature of outlet:
(1) 200 K
(2) 400 K
(3) 600 K
(4) 800 K
​

Answer 1

Answer:

400 K.

Explanation:

Given :

Efficiency = 50 % or 50 / 100 = 1 / 2

We know :

Efficiency = Work done / Heat given

η = W / Q or 1 - T₂ / T₁

We also have

T₂ = 500 K

= >  T₁ = 1000

In second case ;

η = 60%

60 / 100 = 1 - T'₂ / T₁

T'₂ = 500 × 4 / 5

T'₂ = 400 K

Hence , temperature of outlet is 400 K.