9) Evaluate [i^18 + (1/i)^25]^3
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0
Answer:
Answer
Given,
[i
18
+(
i
1
)
25
]
3
=(i
18
+
i
25
1
)
3
=(−1+
i
1
)
3
=(−1)
3
+3(−1)
2
i
1
+3(−1)(
i
1
)
2
+(
i
1
)
3
=
i
2
+2
=−2i+2
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