Question

9. Evaluate the following at x=-1, y = -2. z = 0 : (ii) (x + y)² – (y + z)²– (x + z)² – 3 xyz +4​

Answer 1

Answer:

For the pair of equations θx+3y + 7 =0 and 2x + 6y -14 =0, to have infinitely many solutions, the value of θ should be 1. Is the statement true? Give reasons.

Step-by-step explanation:

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