9. Factorise 1-64a³-12a+48a².
Answers
Answered by
2
1-64a^3-12a+48a^2
= (1-4a)^3
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Answered by
4
Step-by-step explanation:
Hi friend,
→1-64a³-12a+48a²
=(1)³-(4a)³-3(1)²(4a)+3(1)(4a)²
This is in the form of a³-b³-3a²b+3ab².
So,a³-b³-3a²b+3ab² = (a-b)³
Here,
a=1,b=4a
So,
(1)³-(4a)³-3(1)²(4a)+3(1)(4a)² = (1-4a)³
So,answer is (1-4a)³
★hope it helps★
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