Math, asked by sreedevisrinivasan, 1 year ago

9. Factorize:
 {x}^{4} + {x }^{2} + 25

fastest answer with explanation is the brainliest

Answers

Answered by Brâiñlynêha
3

\huge\mathbb{SOLUTION:-}

\sf \bullet x{}^{4}+x{}^{2}+25

We have to factorize this

Now :-

  • 2 identities are used

\boxed{\sf{(a+b){}^{2}=a{}^{2}+b{}^{2}+2ab}}

\boxed{\sf{a{}^{2}-b{}^{2}=(a+b)(a-b)}}

\sf\underline{\pink{\:\:\:\: Solution:-\:\:\:\:}}

\sf \implies x{}^{4}+x{}^{2}+25\\ \\ \sf\implies (x{}^{4}+10x{}^{2}+25)-9x{}^{2}\\ \\ \sf\implies it\: became\:in\:the\:form\:of\\ \\ \sf\:\:\:a{}^{2}-b{}^{2}=(a+b)(a-b)\\ \\ \sf\implies  (x{}^{2}+5){}^{2}-(3x){}^{2}\\ \\ \sf\implies (x{}^{2}+5+3x)(x{}^{2}+5-3x)\\ \\ \sf\implies \:or\: (x{}^{2}+3x+5)(x{}^{2}-3x+5)

\boxed{\sf{\therefore x{}^{4}+x{}^{2}+25=(x{}^{2}+3x+5)(x{}^{2}-3x+5)}}

Answered by TRISHNADEVI
0

 \huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \:   \: SOLUTION \:  \: } \mid}}}}}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \mathcal{ \underline{ \underline{ \blue{ \:  \: TO \:  \:  \:   FACTORISE : \leadsto \:  \: }}}}

 \:  \:  \:  \:  \:  \tt{x {}^{4} + x {}^{2}  + 25 } \\  \\  \tt{ = x {}^{4} + 10x {}^{2}  - 9x {}^{2}   + 25} \\  \\  \tt{ = (x {}^{4}  + 10x {}^{2}  + 25) - 9x {}^{2} }

 \underline{ \mathfrak{Now,}} \\  \\    \:  \:  \: \underline{\text{ \: Factorizing the expression \: } }  \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \red{ \boxed{ \bold{x {}^{4}  + 10x {}^{2}  + 25}}}

 \underline{ \text{ \:  \: Identity \:  \:  used :-  \:  \: }} \\  \\   \:  \:  \:  \:  \:  \: \underline{ \boxed{ \bold{ \:  \: a {}^{2}  + 2ab + b {}^{2} = (a + b) {}^{2} }}}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \tt{x {}^{4}  + 10x {}^{2} + 25 } \\  \\  \tt{ = (x {}^{2} ) {}^{2} + 2 \times x {}^{2}  \times 5 + (5) {}^{2}  } \\  \\  \tt{ = (x {}^{2} + 5) {}^{2}  } \:

  \tt{ \therefore \:  \underline{\red{ \: (x {}^{4} + 10x {}^{2}  + 25) - 9x {}^{2} = (x {}^{2}  + 5) {}^{2}  - 9x {}^{2}  \: } } }

 \underline{ \mathfrak{Now,}} \\  \\    \:  \:  \: \underline{\text{ \: Factorizing the expression \: } }  \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \red{ \boxed{ \bold{(x {}^{2} + 5) {}^{2}   - 9x {}^{2} }}}

 \underline{ \text{ \:  \: Identity \:  \:  used :-  \:  \: }} \\  \\   \:  \:  \:  \:  \:  \: \underline{ \boxed{ \bold{ \:  \: a {}^{2}   -  b {}^{2} = (a + b) (a - b)}}}

 \:  \:  \:  \:  \:  \:  \:  \tt{(x {}^{2} + 5) {}^{2} - 9x {}^{2}   } \\  \\ \tt{ = [(x {}^{2} + 5) + 9x] [x {}^{2} + 5) - 9x ]  }  \\  \\  \tt{ = (x {}^{2}  + 5 + 9x)(x {}^{2}  + 5 - 9x)} \\  \\  \tt{ = (x {}^{2}  + 9x + 5)(x {}^{2}   -  9x + 5)}

\therefore \:  \boxed{ \boxed{ \tt {\red{ \: x {}^{4} + x {}^{2}  + 25 = (x {}^{2}  + 9x + 5)(x {}^{2}   -  9x + 5) \: }}}}

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