Physics, asked by alexadsouza1884, 10 months ago

9. Figure shows two cases. In first case a spring (spring
constant K) is pulled by two equal and opposite forces
Fat both ends and in second case is pulled by a
force Fatone end. Extensions (x) in the springs will be
Fm
case(1)
case(2)
2
(1) In both cases x = 2f/k
(2) In both cases X
f/k
(3) In first case x = 2f/k
, in second case X =f/k
(4) In first case X =f/k
in second case x=2f/k​

Answers

Answered by Tonystark1XT
3

Answer:

Explanation:

onstant K) is pulled by two equal and opposite forces

Fat both ends and in second case is pulled by a

force Fatone end. Extensions (x) in the springs will be

Fm

case(1)

case(2)

2

(1) In both cases x = 2f/k

(2) In both cases X

f/k

(3) In first case x = 2f/k

, in second case X =f/k

(4) In first case X =f/k

in second case x=2f/k​

Answered by vardaanbansal5
0

Explanation:

this will be the answer

upward answer is wrong

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