9. Figure shows two cases. In first case a spring (spring
constant K) is pulled by two equal and opposite forces
Fat both ends and in second case is pulled by a
force Fatone end. Extensions (x) in the springs will be
Fm
case(1)
case(2)
2
(1) In both cases x = 2f/k
(2) In both cases X
f/k
(3) In first case x = 2f/k
, in second case X =f/k
(4) In first case X =f/k
in second case x=2f/k
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Answer:
Explanation:
onstant K) is pulled by two equal and opposite forces
Fat both ends and in second case is pulled by a
force Fatone end. Extensions (x) in the springs will be
Fm
case(1)
case(2)
2
(1) In both cases x = 2f/k
(2) In both cases X
f/k
(3) In first case x = 2f/k
, in second case X =f/k
(4) In first case X =f/k
in second case x=2f/k
Answered by
0
Explanation:
this will be the answer
upward answer is wrong
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