Question

9. Find impulse given to particle at t=2s. If mass of particle is 2kg X(M) 40 t(s) 2​

Answer 1

Answer:

Given,

Velocity, v=(2t

i

^

+4

j

^

)

Change in velocity at time(t=2secandt=0), Δv=v

t=2

−v

t=0

=(4

i

^

+4

j

^

)−4

j

^

=4

i

^

.

Impulse, I=F.Δt=mΔv=2×4

i

^

=8

i

^

Hence, impulses is 8

i

^

Answer 2

Answer:

-40 N-s

Explanation:

velocity of particle 0-2 sec = 40/2 = 20 m/s

velocity after 2 sec is = 0

Therefore, ∆p or impulse ( at t = 2 ) =

I = final p - initial p = m×0 - m×20

= -40 N-s