Question

9. Find median of the following:
133, 73, 89, 108, 94, 104, 94, 85, 100, 120
а) 56
b)97 c)34 d)53
​

Answer 1

Step-by-step explanation:

arranging them in ascending order we get=73,85,94,94,100,108,120,133

so median is LCM of 94 and 94

Answer 2

Solution:-

To find :-

• Median

Formula:-

1)If n is even then,

Median:-

$\frac{( \frac{n}{2}) th \: term + ( \frac{n}{2} + 1)th \: term}{2}$

2)If n is odd then.

Median:-

$( \frac{n + 1}{2}) th \: term$

1. First we have to arrange this given data into ascending or descending order.

Ascending order:-

73 , 85 , 89 , 94 , 94 , 100 , 104 , 108 , 120 , 133

So , n = 10( Even)

So , 1st formula will be used.

By the problem:-

$\frac{( \frac{n}{2}) th \: term + ( \frac{n}{2} + 1)th \: term}{2}$

Plot the value:-

$\frac{( \frac{10}{2}) th \: term + ( \frac{10}{2} + 1)th \: term}{2} \\ = > \frac{( 5) th \: term + ( 5 + 1)th \: term}{2} \\ = > \frac{( 5) th \: term + ( 6)th \: term}{2} \\ = > \frac{100 + 94}{2} \\ = > \frac{194}{2} \\ = > 97$

Answer:-

97. (Option B)