Question

9.Find n such that 2^11÷2^5=2^(-3)×2^( 2 n -1)​

Answer 1

Answer:

Step-by-step explanation:

n = 5

2^11 / 2^5 = 2^-3 x 2^(2n - 1)

=> 2^(11 - 5) = 2^(-3 + 2n - 1)  ------->  By identity a^m / a^n = a^(m - n) and

                                                                            a^m x a^n = a^(m + n)

=> 2^6 = 2^(2n - 4)

Equating exponents,

=> 6 = 2n - 4

=> 10 = 2n

∴ n = 5

Hope this helps! :