Question

9) Find p(0), p(1),and p(-1) for the each of the following polynomials:



(a) x²+2x+1. ( b) x²-1​

Answer 1

Step-by-step explanation:

a)

p(-1) = (-1)^2+2(-1) +1

= 1 + (-2) +1

= -2+2

= 0

b)

p(1)=(1)^2 -1

= 1-1

= 0

or

p(-1)=(-1)^2 +1

= 1-1

= 0