Question

9. Find points on the x-axis, each of which is at a distance of 10 units from
the point A(11,-8).
10. Find the point on the y-axis which is equidistant from the points A(6,5)​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let the points on x-axis be P(x,0) and Q(y,0) which are at distance of 10 units from point A(11,−8)

Which implies:

PA=QA

or PA

2

=QA

2

(11−x

1

)

2

+(−8)

2

=(11−x

2

)

2

+(−8)

2

=10

2

(11−x)

2

+(−8)

2

=10

2

121=22x+x

2

+64=100

x

2

−22x+85=0

x

2

−12x−5x+85=0

x(x−17)−5(x−17)=0

(x−17)(x−5)=0

Either (x−17)=0 or (x−5)=0

x=17 or x=5

So, the points are: (17,0) and (5,0).