Question

9. Find the 10th term of the AP: 2, 7, 12....​

Answer 1

||GIVEN||

• 2,7,12... are in arithmetic progression [AP].

||TO FIND||

• 10th term of the given AP.

||SOLUTION||

$\sf{a_1 = 2}$

$\sf{a_2 = 7}$

$\sf{a_3 = 12}$

$\boxed{\sf{\star\;Common\; Difference [d] = a_2-a_1}}$

$d = 7 - 2 \\ d = 5$

Common Difference [d] = 5

$\boxed{\sf{\star\;nth\;term = a_1+(n-1)d}}$

10th term = a+(10-1)d

$2 + (10 - 1)5 \\ 2 + (9)5 \\ 2 + 45 \\ 47$

Required 10th Term

• $\longmapsto\;\bold{47}$

$\tt{@MrMonarque}$

Hope It Helps You ✌️

Answer 2

QUESTION :- Find the 10th term of the AP: 2, 7, 12 . . .

ANSWER :-

GIVEN :-

⇒AP : 2, 7, 12 . . .

TO FIND :-

⇒ 10th term of AP

SOLUTION :-

$\sf{a_1 = 2}$

$\sf{a_2 = 7}$

$\sf{a_3 = 12}$

$\fbox{\sf {\ Common \: Difference \: [d] = {a_2} - {a_1}}}$

$d = 7 - 2$

$\fbox{d = 5}$

✿ Common Difference [d] = 5

To find the nth term we use the formula,

$\fbox{\sf {nth \:term = {a_1} + (n - 1)d}}$

10th term = $\sf{a + (10 - 1)d}$

$= 2 + (10 - 1)5$

$= 2 + (9)5$

$= 2 + 45$

$= 47$

∴ The 10th term of AP given is 47.