Question

9. Find the 4th term of thfollowing arithmetic progression root 2, root8, root 18​

Answer 1

Step-by-step explanation:

$a = t1 = \sqrt{2} \\ t2 = \sqrt{8} = 2 \sqrt{2} \\ d = t2 - t1 = 2 \sqrt{2} - \sqrt{2} = \sqrt{2} \\ \\ tn = a + (n - 1)d \\ t4 = 4 \sqrt{2} = \sqrt{32}$

Answer 2

AP= root 2, root 8, root 18

d=root 8-root 2

A4= A+2d

A4= root 2 + 2(root 8- root 2)

A4= root 2 + root 16 - root 4)

root 6 is 4 and root 4 is 2

A4= root2 + 4-2

A4= root 2 +2

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A4= 2root 2.

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