Question

9) Find the altitude at which
the accen due to gravity is
25% of that the rearth's surface.​

Answer 1

Answer:

For this question,

We have the formula, g' = g/(1+h/R)^2

Explanation:

Here g' = acceleration due to gravity at the height

g = 9.8m/s^2

R = radius of earth

h = height

g/g' = (1+h/R)^2

4 = (1+h/R )^2

1+h/R = 2

h/R = 1

h = R

So at the height of 6371 km the value of g is 1/4 th of its original value

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