Question

(9.) Find the amount to be paid at the end of 3 years in each case:
(a) Principal = Rs 1.200 at 12%p.a. (b) Principal = R$7,500 at 5% pa​

Answer 1

Answer:

a.1.200+0.432=1.632

$12 \times 6 \times 3 \div 500 = 0.432$

b.7500+1125=8625

$7500 \times 5 \times 3 \div 100 = 1125$

follow me

Answer 2

For part A refer the attachment above ⚡

Part B

Answer:-

₹ 8625

Step-by-step explanation:-

P = ₹7500

R = 5%

T = 3 years

$\sf{ S.I. = \dfrac{ = P \times R \times T}{100}}$

$\sf{S.I. = \dfrac{7500 \times 5 \times 3}{100} }$

$\sf{S.I. = \dfrac{75 \cancel{00} \times 5 \times 3}{ \cancel{100}}}$

$\sf{S.I. = 75 \times 5 \times 3}$

S.I. = ₹1125

Now, for finding Amount,

A = P + I

A = 7500 + 1125

A = ₹8625

Therefore, Amount paid at the end of 3rd year = ₹8625

Here,

P = Principal

R = Rate

T = Time

S.I. = Simple interest

A = Amount

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬