9. Find the angle whose supplement is four times its complement
10. Find the angle whose complement is one third of its supplement
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✨Heya dear✨
9. let one angle be x
the other angle = 180-x supplement
90-x = compliment
180-x=4*(90-x) supplement is 4 times compliment
180-x = 360 -4x
3x= 360-180
3x=180
X=60 deg
10. Let the angle be x complement of x is (90 − x)°
supplement of x is (180 − x)°
Given (90 − x)° = (1/3) × (180 − x)°
⇒ 270° − 3x = 180°− x
⇒ 270° − 180° = 3x − x
⇒ 2x = 90°
∴ x = 45°
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