Question

9. Find the area of a circle of radius 14 cm (use π = 3.14)


​

Answer 1

Answer:

Area of circle = 615.44$cm^{2}$

Step-by-step explanation:

According to the information provided in the question it is given as

Radius  = 14 cm

(use π = 3.14)

We need to find the area of circle

The area of a circle is the space occupied by the circle in a two-dimensional plane. Alternatively, the space occupied within the boundary/circumference

By applying the formula

Area of circle = $\pi r^{2}$

$A = 3.14 \times 14^{2} \\A =3.14 \times 14\times 14\\A = 3.14\times 196\\A= 615.44cm^{2}$

Hence area of circle is 615.44$cm^{2}$

Answer 2

Question :-

• Find the Area of Circle, whose Radius is 14 cm .

⠀

Answer :-

• Area of Circle is 615.44 cm² .

$\rule {190pt}{2pt}$

Given :-

• Radius of Circle = 14 cm .

⠀

To Find :-

• Area of Circle = ?

⠀

Solution :-

• Here, Radius is given 14 cm . And, we have to find Area .

⠀

➻ Formula Required :-

• $\sf{ Area \: of \: Circle = \pi {r}^{2} }$

⠀

➻ Where ,

• R denotes to the Radius .

⠀

➻ By substituting the values :-

$\dag \: \: \sf{Area \: of \: Circle = \pi {r}^{2} }$

$\Longrightarrow \: \: \sf{Area \: of \: Circle \: = \: 3.14 \: \times \: ( {14})^{2} }$

$\Longrightarrow \: \: \sf{Area \: of \: Circle \: = \: 3.14 \: \times \: 14 \: \times \: 14}$

$\Longrightarrow \: \: \sf{Area \: of \: Circle \: = \: 43.96 \: \times \: 14}$

$\Longrightarrow \: \: \sf{Area \: of \: Circle \: = \: 615.44 \: {cm}^{2} }$

⠀

Hence :-

• Area = 615.44 cm² .

$\rule {190pt}{4pt}$

$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \pmb {\sf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Square = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \sf{Area \: of \: Rectangle = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Triangle = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Parallelogram = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Trapezium = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf {Area \: of \: Rhombus = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$