Question

9. Find the area of a rhombus whose one side is 15 cm and one diagonal is 24 cm.
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Answer 1

Answer:

432 cm²

Step-by-step explanation:

Let rhombus be ABCD and intersect at point O.

Then, OB=OD=24/2=12 cm (Diagonals bisect each other)

In Right Triangle DOC,

By Pythagoras Property,

Hypotenuse²=Base²+Altitude²

Base²=Hypotenuse²-Altitude²

  OC²=DC²-OD²

  OC²=15²-12²

  OC²=(15+12)(15-12)

   OC=√27 ×3

   OC=√3×3×3×3

   OC=3×3

   OC=9 cm

Then, AC=9×2=18 cm (Diagonals bisect each other)

Area of a Rhombus=d₁×d₂

Area of a Rhombus=18×24

Area of a Rhombus=432 cm²

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Answer 2

Answer:

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432cm²

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