Question

9. Find the area of the following trapezium: PQRS
PQ= 12cm
SR=6cm
Height=4cm​

Answer 1

Answer:

Area of trapezium=

$\frac{1}{2} \times (sum \: of \: parallel \: sides) \times height \\ \\ \frac{1}{2} \times (18) \times 4$

Therefore ans is 36 cm²

Answer 2

Answer:

Here, PQ = 12cm , SR = 6cm , Height = 4cm

Therefore,

Area of a trapezium = 1/2 × (PQ + SR) × Height

= 1/2 × (12 + 6) × 4

= 1/2 × 18 × 4

= 36 cm^2 ans.

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