Question

9. Find the difference between compound
interest and simple interest on 12,000 and
1
in 1
2
years at 10% p.a. compounded yearly.​

Answer 1

Answer:

Given, P= Rs. 1200,R=10% p.a., T=1 years

∴S.I.=

100

P×R×T

=

100

1200×10×1

= Rs. 120

For C.I. reckoned half yearly, P= Rs. 1200,r=5% per half year, n=2 half year

∴ C.I. = Rs. (1200(1+

100

5

)

2

−1200) = Rs. ((1200×

20

21

×

20

21

)−1200)

= Rs. 1323− Rs. 1200= Rs. 123

∴ Required difference = Rs. 123− Rs. 120= Rs. 3

.

.

.

. HOPE IT WILL HELPFUL.

. MARK ME AS BRILLIANT☺