9.
Find the equation of straight lines passing through (-2,- 7) and having an intercept of length 3
units between the straight lines 4x + 3y = 12, 4x + 3y = 3.
please solve it step by step
Answers
Answered by
1
Answer:
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Step-by-step explanation:
first distance between parallel lines is
(
a
2
+b
2
)
c1−c2
=
5
9
now consider triangle ABC
BC=
(
3
2
−(
5
9
)
2
)
=
5
12
now tanθ=
BC
AC
=
4
3
now angle between 2 lines is tanθ=
1+m1m2
m1−m2
4
3
=
1−
3
4m
m1+
3
4
m=
24
−7
so slope m=
24
−7
and passing through point (-2,-7)
equation is (y+7)=−(x+2)
24
7
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therefore equation is 7x+24y+182=0
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