Math, asked by rs4641343, 5 months ago


9. Find the greatest number which will divide 410, 751 and 1030 so as to
leave the remainder 7 in each case.
10.)
A sweet seller has 420 kaju burfis and 130 badam burfis. She wants to
stick them in such a way that each stack has the same number, and they
take up the least area of the tray. What is the number that can be placed
in each stack for this purpose?
ld uninhine 3318 and 3054 qram respectively are to be​

Answers

Answered by kashishtomar48
1

Answer:

firstly we take HCF of

420 & 130

the HCF of 420 & 130 is 10

Answered by jagruthyc
0

Answer:

for finding no.dividing 470,751,1030 leaving remainder 7, the HCF of the no . will be 470-7 ,751-7 ,1030-7.

the HCF of the nymbers 403,744,1023 is 31

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