9. Find the least number which when divided by 20, 25, 30, and 36 leaves a remainder 4 in each case.
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Answer:
904 is the number
Step-by-step explanation:
The prime factors of 20,25,33 and 36 are
20=2^2*5
25=5*5
30=2*3*5
36=2*2*3*3
Thus LCM=2*2*3*3*5*5=900
In each case the remainder is 4
So the number= 900+4=904
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