Math, asked by monika88vermabpl, 6 months ago

9. Find the least number which when divided by 20, 25, 30, and 36 leaves a remainder 4 in each case.​

Answers

Answered by harrpunniyakotti3
1

Answer:

904 is the number

Step-by-step explanation:

The prime factors of 20,25,33 and 36 are

20=2^2*5

25=5*5

30=2*3*5

36=2*2*3*3

Thus LCM=2*2*3*3*5*5=900

In each case the remainder is 4

So the number= 900+4=904

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