Question

9. Find the mean of ten new born babies born in a
particular hospital on a particular day.
3.4 kg, 3.6 kg, 3.0 kg, 4.0 kg, 2.5 kg, 3.6 kg, 3.8 kg,
2.8 kg, 3.2 kg, 2.6 kg.
10. The numbers of family members in ten families of
a locality are as follows:
4, 3, 2, 2, 5, 6, 7, 3, 3, 5.
(a) Find the mean size of family member of the
above ten families.
(b) How many families have their number of
members more than the​

Answer 1

9: mean is 3.25

step-by-step explanation

mean= 3.4+3.6+3.0+4.0+ 2.5+3.6+3.8+2.8+3.2+2.6 /10

=32.5/10

= 3.25

10 a: mean=4+3+2+2+5+6+7+3+3+5/10

=40/10

= 4

b: How many families have their number of

members more than the⁉️⁉️❓❓____

Answer 2

Step-by-step explanation:

• Q.9) Question :

Find the mean of ten new born babies born in a

particular hospital on a particular day.

3.4 kg, 3.6 kg, 3.0 kg, 4.0 kg, 2.5 kg, 3.6 kg, 3.8 kg,

2.8 kg, 3.2 kg, 2.6 kg.

• ✰ sᴏʟᴜᴛɪᴏɴ :

$mean \: of \: ungrouped \: data \: = \frac{sum \: of \: observsation}{no. \: of \: observation}$

As per the Question there are 10 Observation and There Sum

$= 3.4 + 3.6 + 3.0 + 4.0 + 2.5 + 3.6 + 3.8 + 2.8 + 3.2 + 2.6 = 32.5$

$Mean \: = \frac{32.5}{10} = 3.25$

Therefore, mean = 3.25

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