9. Find the number of sides of a regular polygon if each of its interior angle is168°.
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Answer:
No. of sides of a regular polygon=n
Each interior angle=168°
each exterior angle=180-168=12°no.of sides of regular polygon=360/each exterior angle
=360/12
=30sides
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Number of sides of a polygon be n.
Sum of interior angles of regular polygon = (n - 2)*180
Each interior angle of regular polygon = (n - 2)*180/n
Given
Each interior angles of regular polygon = 168 degrees
(n - 2)*180/n = 168
(n - 2)/n = 168/180
1 - (2/n) = 168/180
2/n = 1 - 168/180
2/n = (180 - 168)/180
2/n = 12/180
1/n = 6/180
1/n = 1/30
n = 30
Therefore number of sides of a given polygon are 30. ——> Answer.
Sum of interior angles of regular polygon = (n - 2)*180
Each interior angle of regular polygon = (n - 2)*180/n
Given
Each interior angles of regular polygon = 168 degrees
(n - 2)*180/n = 168
(n - 2)/n = 168/180
1 - (2/n) = 168/180
2/n = 1 - 168/180
2/n = (180 - 168)/180
2/n = 12/180
1/n = 6/180
1/n = 1/30
n = 30
Therefore number of sides of a given polygon are 30. ——> Answer.
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