World Languages, asked by nisaajinisa, 3 months ago

9. Find the Oxidation number of the elements 1)Mno
ii) Mn 07
iii) MgCL
iv)MgO
(Hint: Oxidation number of 0=-2. CI=-1)​

Answers

Answered by albindshibu
1

Explanation:

MnO

2

Let x be the oxidation number of Mn

x+(−2)×2=0

x+(−4)=0

x=+4

MnO

7

2Mn+(−2)×7=0

2Mn+(−14)=0

2Mn=14

Mn=

2

+14

=+7

K

2

Cr

2

O

7

Let x be the oxidation number of Cr is x

+1×2+2x+(−2)×7=0

+2+2x+(−2)×7=0

2x+(−12)=0

2x=+12

x=

2

+12

=+6

KCrO

3

+1+Cr+(−2)×3=0

+1+Cr+(−6)=0

Cr+(−5)=0

Cr=+5

MnCl

2

Let x be the oxidation of Mn

x+(−1)×2=0

x+(−2)=0

x=+2

MgO Let x be the oxidation number of Mg

x+(−2)=0

x=+2

MgCl

2

x+(−1)×2=0

x+(−2)=0

x=+2

Al

2

O

3

Let x be the oxidation number of Al

2x+(−2)×3=0

2x+(−6)=0

2x=+6

x=

2

+6

=+3

AlCl

3

x+(−1)×3=0

x+(−3)=0

x=+3

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