9. Find the Oxidation number of the elements 1)Mno
ii) Mn 07
iii) MgCL
iv)MgO
(Hint: Oxidation number of 0=-2. CI=-1)
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Explanation:
MnO
2
Let x be the oxidation number of Mn
x+(−2)×2=0
x+(−4)=0
x=+4
MnO
7
2Mn+(−2)×7=0
2Mn+(−14)=0
2Mn=14
Mn=
2
+14
=+7
K
2
Cr
2
O
7
Let x be the oxidation number of Cr is x
+1×2+2x+(−2)×7=0
+2+2x+(−2)×7=0
2x+(−12)=0
2x=+12
x=
2
+12
=+6
KCrO
3
+1+Cr+(−2)×3=0
+1+Cr+(−6)=0
Cr+(−5)=0
Cr=+5
MnCl
2
Let x be the oxidation of Mn
x+(−1)×2=0
x+(−2)=0
x=+2
MgO Let x be the oxidation number of Mg
x+(−2)=0
x=+2
MgCl
2
x+(−1)×2=0
x+(−2)=0
x=+2
Al
2
O
3
Let x be the oxidation number of Al
2x+(−2)×3=0
2x+(−6)=0
2x=+6
x=
2
+6
=+3
AlCl
3
x+(−1)×3=0
x+(−3)=0
x=+3
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