Question

9. Find the perimeter of the following


An isosceles triangle whose equal sides are 10 cm each and unequal side is 15 cm​

Answer 1

Answer:

equal sides = 10 cm

unequal side =15 cm

perimeter of isosceles triangle

=2a+b

=2×10+15

=20+15

=35 cm

Answer 2

$\Large{\green{\underline{\underline{\overline{\bf{\diamond\;SoluTion:}}}}}}$

Given,

Triangle is an Isosceles

In an Isosceles ∆le 2 Sides are Equal

If Let ∆le be ABC

Then, AB = AC = 10cm & BC = 15cm

$\boxed{\sf{Perimeter = Length\;of\;All\;Sides}}$

$→\;{\bf{AB+BC+CA}}$

$→\;{\bf{10+15+10}}$

$→\;{\sf{35\;cm}}$

Perimeter of Isosceles ∆le is ◕➜ $\fbox\red{35cm}$

Hope It Helps You :)