9. Find the perimeter of the rectangle whose length is 60 cm and a diagonal is 61 cm.
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Given :-
- Length = 60 cm
- Diagonal = 61 cm
To Find :-
- Breadth = ?
- Perimeter of the rectangle = ?
Solution :-
Let ΔPQRS be the given triangle such that PQ = RS = 60 cm and PR = 61 cm.
Refer to the attachment given ⇫
In ΔPQR,
➞ (PR)² = (PQ)² + (QR)²
➞ (61)² = (60)² + (QR)²
➞ QR² = 3721 – 3600
➞ QR² = 121
➞ QR = 11
Hence, Breadth = 11 cm
Perimeter of the rectangle :-
➪ 2(l + b)
➪ 2(60 + 11)
➪ 2 × 71
➪ 142
∴ Perimeter of the rectangle = 142 cm.
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