Question

9. Find the slope of the tangent on the curve
x2 + y2 - 4x - 1 = 0 at (3, 2)​

Answer 1

Given :  x² + y² - 4x - 1  = 0

To Find : Slope of the tangent  at ( 3 ,2 )

Solution:

x² + y² - 4x - 1  = 0

=> 2x  + 2y dy/dx  - 4   = 0

=> x + y dy/dx  - 2   = 0

=> y dy/dx    = 2 - x

=> dy/dx   = (2 - x)/y

at ( 3 , 2)

x = 3 , y = 2

Slope =  (2 - x)/y  

= (2 - 3) / 2

= - 1/2

Slope of the tangent  at ( 3 ,2 ) = - 1/2

Learn More:

The tangent to the curve y = x2 + 3x will pa s through the point 0, - 9 ...

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the slope of the line 2x+2y =2 is equal to​ - Brainly.in

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Answer 2

Step-by-step explanation:

answer of this question is -1/2