Question

9. Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32
respectively.
10. What is the smallest number that, when divided by 35, 56 and 91 leaves remainders of 7​

Answer 1

Step-by-step explanation:

this is answer of this question

Answer 2

Answer:

Given that the smallest no. When divided by 28 & 32 leaves remainder 8 & 12. Therefore, 28–8=20 & 32–12=20 are divisible by the required number will be 20 less than the LCM of 28 and 32. Hence, the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 is 204