Question

9. Find the smallest number which when divided by 15, 20, 25 and 30 leaves 5 as remainder in each case​

Answer 1

Answer:

The the smallest number which when divided by 15, 20, 25 and 30 leaves a remainder 5 is 305.

Answer 2

Step-by-step explanation:

first divide all the terms 15 20 25 30 and then it's solve by remainder theorem so u solve by self i can't solve in mobile