Question

9. Find the sum of the degree measures of the interior angle of a hexagon and an octagon a decagon​

Answer 1

Answer:

(i) Hexagon

Numbers of sides, n=6

Sum of the interior angles =(2n–4)90°

=((2×6)–4)×90°

=(12–4)90°

=8×90°=720°

Sum of the exterior angles =360°.

(ii) Octagon

Numbers of sides, n=8

Sum of the interior angles =(2n–4)90°

=((2×8)–4)×90°

=(16–4)90°

=12×90°

=1080°

Sum of the exterior angles =360°

(v) Decagon

Numbers of sides, n=10

Sum of the interior angles =(2n–4)90°

=((2×10)–4)×90°

=(20–4)90°

=16×90°

=1440°

Sum of the exterior angles =360°

Step-by-step explanation:

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