Question

9.
Find the total surface area of a hollow cylindrical pipe open at the ends if its height is
10 cm, external diameter 10 cm and thickness 12 cm (use 1 =3.14).
: 1002mondofth​

Answer 1

Step-by-step explanation:

Maths

Find the total surface area of a hollow cylinder open at both ends, if its length is 12\ cm12 cm, external diameter is 8\ cm8 cm and the thickness is 2\ cm2 cm.

December 26, 2019avatar

Malavika Castelino

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ANSWER

Given for the hollow cylinder with open at both ends, length is h=12\ cmh=12 cm, external diameter is 8\ cm8 cm and the thickness is 2\ cm.2 cm.

Then external radius is r_1=4r

1

=4 cm and internal radius isr_2=4-2=2r

2

=4−2=2 cm.

Now the total surface area of the hollow cylinder will be,

=2\times \pi\times (r_1-r_2)\times h=2×π×(r

1

−r

2

)×h

=2\times \pi\times (4-2)\times 12=2×π×(4−2)×12

=48\pi=48π cm^2

2

Answer 2

Answer:

Total surface of hollow cylindrical pipe

Total surface of hollow cylindrical pipe= 2π[Rh+rh+(R²-r²)]

Total surface of hollow cylindrical pipe= 2π[Rh+rh+(R²-r²)]= 2π[(4)(12)+(2)(12)+(4²-2²)] cm²

Total surface of hollow cylindrical pipe= 2π[Rh+rh+(R²-r²)]= 2π[(4)(12)+(2)(12)+(4²-2²)] cm²=2π(48+24+12) cm²

Total surface of hollow cylindrical pipe= 2π[Rh+rh+(R²-r²)]= 2π[(4)(12)+(2)(12)+(4²-2²)] cm²=2π(48+24+12) cm²=2π(84) cm²

Total surface of hollow cylindrical pipe= 2π[Rh+rh+(R²-r²)]= 2π[(4)(12)+(2)(12)+(4²-2²)] cm²=2π(48+24+12) cm²=2π(84) cm²=168π cm²