Question

9. Find the value of current in following circuit.
т
300 (R)
V
30.0
(R3)
2y
330-12 (R2)
T​

Answer 1

Answer:

0.1 amperes

Explanation:

Given :

• Two 30 ohms resistors are connected in series and one 30 ohms resistor is connected in parallel to them
• Voltage or potential difference is 2 Volts

To find :

• Current across the battery

First we need to find the equivalent resistance and use the ohms law to find the current

30 ohms in series:

Equivalent resistance = 30+30

Equivalent resistance = 60 ohms

Now 60 is on parallel to 30:

1/r = 1/60+1/30

1/r = 1/60+2/60

1/r = 3/60

r = 60/3

r = 20 ohms

V=IR

2=I×20

I=2/20

I=0.1 amperes

Answer 2

Answer :

Here 1st and 2nd resistances are in series.

$\implies \bold{R_{12}=R_1+R_2}\\\\\implies R_{12}=30\;\Omega+30\;\Omega\\\\\bold{\implies R_{12}=60\;\Omega}$

Now 3rd and 1st,2nd are in parallel.

$\implies\bold{ \frac{1}{R_{123}} =\frac{1}{R_{12}}+\frac{1}{R_{3}} }\\\\\implies \frac{1}{R_{123}}=\frac{1}{60}+\frac{1}{30} \\\\\implies \frac{1}{R_{123}}=\frac{1}{20} \\\\\implies \bold{R_{123}=20\;\Omega}$

Resistance , R = 20 Ω

Given , Total voltage , V = 2 Volts

Current in the circuit , I = ? Ampere

By using Ohms Law ,

$\implies \bold{V=IR}\\\\\implies \bold{2=I(20)}\\\\\implies \bold{\bf{\blue{I=0.1\;Amperes}}}$