Question

9. find the value of x; y; z in the adjoining figure​

Answer 1

Answer:

y= 130° . Sorry mujhe baki nahi pta Kk

Answer 2

$\purple{solution} \\ \\ \green{given \: that} \\ \green{ \angle A = 30 \degree } \\ \green{ \angle B= 60 \degree}\\ \red{ \: find \: the \: value \: of} \\ \red{ X = ? \: } \red{Y =? } \\ \red{Z = ?} \\ \\ \blue{now} \\ \\ \tt\blue{Y + 60 \degree = \: 180 \degree } \: \: \: \: \green{( \therefore \: linear \: pair \: of \: angles)} \\ \tt \blue{Y = \: 180 \degree - 60 \degree } \\ \tt \blue{ \boxed{ \tt{Y = \: 120 \degree } } } \\ \\ \tt \blue{A +Y + Z = 180 \degree } \: \\ \green{(the \: sum \: of \: all \: the \: three \: interior \: angles \: of \: a \: triangle \: is \: equal \: to \: 108 \degree.)} \\ \tt \blue{30 \degree + 120 \degree + Z = 180 \degree} \\ \tt \blue{150 \degree + Z = 180 \degree} \\ \tt \blue{Z = 180 \degree - 150 \degree} \\ \tt \blue{ \boxed{Z = 30 \degree}} \\ \tt \blue{X +Y = 180 \degree } \: \: \: \: \green{(\therefore \: linear \: pair \: of \: angles)} \\ \tt \blue{X + 120 \degree = 180 \degree} \\ \tt \blue{X = 180 \degree - 120 \degree} \\ \tt \blue{ \boxed{X = 60 \degree}} \\ \\ \huge \tt\pink{ \boxed { \tt{ManishShah98}}}$