9. Find the value of y for which the distance between the points A (3, -1) and
B (11, y) is 10 units,
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Answered by
1
Answer:
y=5
Step-by-step explanation:
A(3,-1) B(11,y)
(AB)^2=(11-3)^2 + (y-(-1))
(AB)^2=(8×8) + (y+1)^2
(10 × 10)=64 + (y+1)^2
100=64 + (y+1)^2
100-64=(y+1)^2
36=(y+1)^2
Square root both sides
6=y+1
6-1=y
5=y
therefore, y=5
Answered by
1
Answer:
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Step-by-step explanation:
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